mysql - Join two rows Distinctly -

-

If I have a table that 

  number 1 2 3 4 5 6 7 8 9

And I want to display the same table in two columns 

  SELECT t1.num, t2.num FROM (SELECT * FROM x ) AS T1, (SELECT * FROM x) AS T2

Then the result set appears 

  Number 1,1 2,2,3, 3,4,4,5,5,6,6,7,7,8,8 9

How do I do this in MySQL

Edit

Sorry, I did not want to make things complicated to start with: But this What is trying to do in the present

To make a bit more clear, what is actually trying to do? 

  num 1,2 2,3 3 , 4,5,5,6,6,7,8,8 9 / <>  
 Do I want to be able to forward:  
  SELECT t2 Note that the above query will return all 1s but the values ​​in my database are appearing individually above   
 Thanks in advance   
 
 
 I do not understand Why do not you just do something simple:  
  SELECT num as num1, num x to  
 
 or if you really want it As a string: 
 
  SELECT CONCAT (num, ',', num) x to num x  
 
 If you select twice the table You can join the table with you, but I do not know why you want to do this: 
 
  Selection Concat (T. 2 NNM) X AS T1 JOIN X AS T2 ON from SX NX Mr. 1 ANM = T2. NAM  
 
 will be more intuitive if you need fields from different rows, like '1,2', '2,3', etc. ... when you make your question So maybe you have some exaggerated things? Are you just trying to learn how to get involved in syntax?

Comments

Post a Comment

Popular posts from this blog

oracle - The fastest way to check if some records in a database table? -

-
I have a big table to work with. I have to see that there are some records whose parent_id is equal to my passing value. Currently I do this by implementing "my_table using select count (*) where parent_id =: id"; If the result> 0, it means that they exist. Because this is a very large table, and I do not care what the actual number of records present, I just want to know if it exists, so I think count (*) Bit is disabled. How do I apply this requirement most quickly? I'm using Oracle 10. # Tips for Hibernation & amp; Tricks It suggests writing in such a way: Integer number = (integer) session .createQuery ("Select Count (*) to ...."). UniqueResult (); I do not know what is the magic of the unique rule? Why does it fast? To compare, select "1 from mytable where parent_id = passId and rowrum", which is more efficient? If you are not interested in the number of records, then there is an EXISTS query one: Select 'y'
Read more

php - multilevel menu with multilevel array -

-
Just ask someone to solve this problem? I want to create a multilevel menu I can not find the right solution generated with multilevel array, it always gets an array_push error My study came from the original idea But still my Can not match the need. This is my MySQL [code] ----- --------------------- --------------- | ID | PARENT_ID | Name | Link | Seq | 1 | 0 | Dashboad | Dashboard / | 1 | 2 | 0 | Menu 1 | Menu 1 / | 2 | 3 | 0 | Menu 2 | Menu 2 / | 3 | 4 | 0 | Menu 3 | Menu 3 / | 4 | 5 | 2 | Joint Add / | 1 | 6 | 3 | Joint Add / | 1 | 7 | 2 | Edit | Edit / | 2 | 8 | 4 | Joint Add / | 1 ------------------------------------------ [/ Code] I want to do something like this in my array array ('dashboard' = & gt; array ('id' = & gt; '' 'Dame' = & gt; 'Dashboard', 'Title' = & gt; 'Dashboard', 'MatchMin' = & gt; Base_URL (). 'Dashboard /', 'Active' => = & Gt; NULL), &
Read more

jQuery UI: Datepicker month format -

-
I am trying to change the format of the month that shows in the popup (not in the date that the picker actually I do not have any choice anywhere to do this, do I like to use a sub-string () or something else? What I normally display is Trying to change: Class = "ui-datepicker-title"> January & lt; / span & gt; ... & lt; / div & gt; Div>
Read more