What is the version number field in the output of the linux file command -

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If I compile the following command on my execution on Fedora Core 11, called "version", I will use this product < Version: ELF 32-bit LSB execution, Intel 80386, version 1 (SysV), dynamically linked (uses libs), GNU / 2.6.18 for

Download Who THEY should version is any use to distinguish?

Whatever I have seen, it is definitely not

  1. kernel version
  2. Libishy version
  3. Something Also do with lsb_release

I want to get some easy identifier to allow customers to know which binary release they should be able to download, which they should be able to identify the ideal By typing a command (such as uname -a, although this is not clearly in this case).

Thank you

This is the kernel version of the machine that is binary compiled < / Em> was turned on. If you use precompold binaries from your distribution, then this distribution is the kernel version of the vendor's machine, perhaps in its compile field.

It is relevant when I consider syscalls that say your binary uses syscall no X and you use a kernel that is X < / Code> does not support or worse than syscall no is allocated to x in a different syscall.

The vanilla linux kernel user API is stable. This means that the linux version a contains the Linux version B if A & lt; All syscall available in = B are available. But it may be that some developers release their own development version of Linux (such as linux-2.6.18-xy ) and if he / she applies a new syscall By compiling a binary using that kernel version, the binary is tagged with that version. So, you are aware that it may or may not be working later on

Btw, /usr/include/asm/unistd_32.h syscall number, Excerpts include:. 

  [...] #define __NR_restart_syscall 0 #define __NR_exit 1 #define __NR_fork 2 #define __NR_read 3 #define __NR_write 4 #define __NR_open 5 [...]

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