c# - Getting Error while read the data from table -

-

I am displaying all the data from the database table in Gridview. I have attached the database file to the app folder but when I am running the application, I am getting the error like

Login can not open the database requested in the 'Employee' login fails User 'HOME-47F64BE31D \ Administrator'

Here's my complete code:

aspx page: 

  & lt; ASP: Gridview id = "Gridview 1" runat = "server" Autogrentech column = "Fotal" & gt; & Lt; Columns & gt; & Lt; ASP: BoundfieldDefined = "Firstname" header text = "Firstname" /> & Lt; ASP: BoundfieldDefined = "Last name" header text = "last name" /> & Lt; ASP: BoundfieldDefined = "Hiredate" header text = "Hiredate" /> & Lt; / Column & gt; & Lt; / ASP: GridView & gt; & Lt; Asp: label id = "lblStatus" runat = "server" & gt; & Lt; / Asp: label & gt;

aspx.cs: 

  protected void Pej_lod (object sender, Iventaarjis e) {if (! IsPostBack) GetData (); } Private Zero GetData () {string str = ConfigurationManager.ConnectionStrings ["ConnectionString"]. ConnectionString; SqlDataAdapter da = New SqlDataAdapter ("GetEmp", str); Da.SelectCommand.CommandType = CommandType.StoredProcedure; Dataset ds = new dataset (); Da.Fill (DS); GridView1.DataSource = DS; GridView1.DataBind (); }

Please help me what is the error?

Your error actually looks like: database access error that HOME-47F64BE31D \ Administrator < / code> the user does not have access to your database, you have two options:

  • for the user to access their database you define through its SQL Management Studio that allow can do.
  • To notify a user with permission in your query string;

With a user with permission User ID = aaa; To add password = BBB , edit your configuration file, in the form of a side note, you will see the sa user in your application


Comments

Post a Comment

Popular posts from this blog

oracle - The fastest way to check if some records in a database table? -

-
I have a big table to work with. I have to see that there are some records whose parent_id is equal to my passing value. Currently I do this by implementing "my_table using select count (*) where parent_id =: id"; If the result> 0, it means that they exist. Because this is a very large table, and I do not care what the actual number of records present, I just want to know if it exists, so I think count (*) Bit is disabled. How do I apply this requirement most quickly? I'm using Oracle 10. # Tips for Hibernation & amp; Tricks It suggests writing in such a way: Integer number = (integer) session .createQuery ("Select Count (*) to ...."). UniqueResult (); I do not know what is the magic of the unique rule? Why does it fast? To compare, select "1 from mytable where parent_id = passId and rowrum", which is more efficient? If you are not interested in the number of records, then there is an EXISTS query one: Select 'y'
Read more

php - multilevel menu with multilevel array -

-
Just ask someone to solve this problem? I want to create a multilevel menu I can not find the right solution generated with multilevel array, it always gets an array_push error My study came from the original idea But still my Can not match the need. This is my MySQL [code] ----- --------------------- --------------- | ID | PARENT_ID | Name | Link | Seq | 1 | 0 | Dashboad | Dashboard / | 1 | 2 | 0 | Menu 1 | Menu 1 / | 2 | 3 | 0 | Menu 2 | Menu 2 / | 3 | 4 | 0 | Menu 3 | Menu 3 / | 4 | 5 | 2 | Joint Add / | 1 | 6 | 3 | Joint Add / | 1 | 7 | 2 | Edit | Edit / | 2 | 8 | 4 | Joint Add / | 1 ------------------------------------------ [/ Code] I want to do something like this in my array array ('dashboard' = & gt; array ('id' = & gt; '' 'Dame' = & gt; 'Dashboard', 'Title' = & gt; 'Dashboard', 'MatchMin' = & gt; Base_URL (). 'Dashboard /', 'Active' => = & Gt; NULL), &
Read more

jQuery UI: Datepicker month format -

-
I am trying to change the format of the month that shows in the popup (not in the date that the picker actually I do not have any choice anywhere to do this, do I like to use a sub-string () or something else? What I normally display is Trying to change: Class = "ui-datepicker-title"> January & lt; / span & gt; ... & lt; / div & gt; Div>
Read more