PHP with Zend Framework can't start a SQLite database? -

-

Trying to get a simple PHP / Zend Framework setup to create and manipulate a SQLite databse. 

  & lt ;? Php require_once ("Zend / Db.php"); // Zend Framework $ db = Zend_Db :: Factory ('Pdo_Sqlite', array ("dbname" = & gt; "./test.sqlite3")); $ Sql ​​= "If the table does not exist then" create tab ". $ Db- & quot; quoteIdentifier (" configs ")." (". $ Db-> quoteIdentifier (" name ")." Text tap primary key, "$ db -> Quotation marker (" value ")." Text not faucet); "; $ sql; $ per second DB-> Query ($ SQL);

In the form of SQL "Exchange does not make" the configuration when creating "(" name "text null is not the primary key) , Tap "value" text); ", which looks correct.

But I get ' Zend_Db_Statement_Exception ' with the 'SQLSTATE [HY000]' message: General Error: 14 Open the database file I have tried to move "pioneer on the variable" ./ "I have been unable to write", and have ensured that the PHP file is allowed to be written for everyone. " Tried to create a file with "test test.sqlite3 " and made sure that it is writeable by everyone

this PH P v5.2.10

Your code is working here (but Windows). Therefore the array ("dbname" => is not a syntax problem)

Some thoughts:

  • If If you are running the program from PHP as an Apache module, then does it work if the command is run by the line? What is the permission of the file created? Adjust the permissions for the Apache user accordingly.
  • If not works on top: strace your script ( strace php test.php ) and for output errors Check it out.
  • In that directory where ./ test.sqlite3 is being created, it should be readable by the user running PHP and writable. This is enough for a readable and writable test.sqlite3 , because sqlite also writes a temporary test.sqlite3-journal and writes that this directory should ensure that it is.
  • Try to use a full path for the database name.
  • Make sure the pdo and pdo_sqlite extensions are loaded (check the output of phpinfo ()) ). Also see that there is no conflict between system and php bundled SQLite labs.

Comments

Post a Comment

Popular posts from this blog

php - multilevel menu with multilevel array -

-
Just ask someone to solve this problem? I want to create a multilevel menu I can not find the right solution generated with multilevel array, it always gets an array_push error My study came from the original idea But still my Can not match the need. This is my MySQL [code] ----- --------------------- --------------- | ID | PARENT_ID | Name | Link | Seq | 1 | 0 | Dashboad | Dashboard / | 1 | 2 | 0 | Menu 1 | Menu 1 / | 2 | 3 | 0 | Menu 2 | Menu 2 / | 3 | 4 | 0 | Menu 3 | Menu 3 / | 4 | 5 | 2 | Joint Add / | 1 | 6 | 3 | Joint Add / | 1 | 7 | 2 | Edit | Edit / | 2 | 8 | 4 | Joint Add / | 1 ------------------------------------------ [/ Code] I want to do something like this in my array array ('dashboard' = & gt; array ('id' = & gt; '' 'Dame' = & gt; 'Dashboard', 'Title' = & gt; 'Dashboard', 'MatchMin' = & gt; Base_URL (). 'Dashboard /', 'Active' => = & Gt; NULL), ...
Read more

c# - TypeConverter in propertygrid only converts from string, not to -

-
When the property grid is reached, only the conversion mechanism (often called) is called "Foo!" Returns the property string in the grid when I click to edit I get an exception Type.oo. Object type can not be changed to type. (Not properly translated,) What is a clue from the convert format, why not? And the error indicates that it is trying to convert to a string, not from. I think that when I want to edit this object, it will have to be converted from foo to string, and when the editing ends. Public class FooTypeConverter: StringConverter {public override object ConvertFrom (ITypeDescriptorContext Reference, CultureInfo Culture, Object Value) {New Foo (string) value); } Convert the public override object (Type the ITE DiskText Contact Reference, CultureInfo Culture, Object Value, Type Type) {Return "Foo!"; } Public override bool CanConvertFrom (ITypeDescriptorContext reference, type source type) {back true; } Public Override Bull CanConvertTo (ITypeDescrip...
Read more

jQuery UI: Datepicker month format -

-
I am trying to change the format of the month that shows in the popup (not in the date that the picker actually I do not have any choice anywhere to do this, do I like to use a sub-string () or something else? What I normally display is Trying to change: Class = "ui-datepicker-title"> January & lt; / span & gt; ... & lt; / div & gt; Div>
Read more