actionscript 3 - Compare Two Arrays, Get Uncommon Values -

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I have a common problem that is having trouble bothering me: 

  var OldValues: array = [4, 5, 6]; Var Newellus: Array = [3, 4, 6, 7];
  1. I want to get value from new values ​​which are not in old prices - 3, 7
  2. I get those values ​​from those old values
  3. One way to add both sets of values ​​of the same kind would be good - 3, 5, 7

I only want to Can I think of a complex method using some nested loops that do nothing redundant? ? Thank you.

You need a bunch of loops, but you can customize them and fully nested Using a loop, a lookup object 

  var old valve: array = [4, 5, 6]; Var Newellus: Array = [3, 4, 6, 7]; Var oldNotInNew: array = new array (); Var newNotInOld: Array = new Array (); Var old makeup: object = new object (); Var i: int; For each one (in old values) {old lookup [i] = true; } For each (in new values) {if (oldLookup [i]) {Delete old lookup [i]; } And {newNotInOld.push (i); }} For (var k: string in old script) {oldNotInNew.push (parseInt (k)); } Trace ("Not old in old:" + old knot in new); Trace ("Not New in Old:" + New Not In Old);

Result:

Not new in old: 5

Not old in new: 3,7


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