scanf - Escape the dot in PHP sscanf? -

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यह काम नहीं करता है: 

  सूची ($ value) = sscanf ('foo .bar ','% s.bar '); प्रतिध्वनि $ मान; //foo.bar

ऐसा करता है: 

  सूची ($ value) = sscanf ('foo बार', '% s बार'); प्रतिध्वनि $ मान; // foo

किसी भी सुझाव वास्तव में सराहना करते हैं धन्यवाद

आप s इस प्रकार: 

  सूची ($ मान) = sscanf ('foo.bar', '% [^।]। बार'); प्रतिध्वनि $ मान; // foo

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